The problem is 2cost−3sin2t+2=0.
I get to 2cost−3sin2t=−2
I think that I need to use a trigonometric identity like cos(x+y) and to divide 2cost−3sin2t with the √22+32
Do you know how to solve this? It should be √22+32
Answer
2cost−3sin2t+2=0. Write sin2t=1−cos2t, then you have a quadratic equation. Solve for cost 2cost−3(1−cos2t)+2=03cos2t+2cost−3+2=0cost=−1,13.
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