Friday, October 13, 2017

calculus - Evaluate limxtoinfty(1+frac2x)5x without L'Hopital



I'm trying to evaluate the following limit



limx(1+2x)5x



I recognize a part of this limit because it resembles the limit for e but I don't know anything other than that. I have no idea where to start. Some hints would be much appreciated.




Thanks!


Answer



Write y=x2. Then we want limy(1+1y)10y. Since the function g(z)=z10 is continuous, this is limyg((1+1y)y)=g(limy(1+1y)y)=(limy(1+1y)y)10=e10.


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