Construct a bijection between $[1,2]$ and $[3,5)$.
So what I usually do if I pair the two outer number together to each other so like $3=1m+b$ and $5=2m+b$ and just solve for m and b but since 5 is not included, I am not sure how to construct it that makes it still a bijection. Thanks for any help!
Edit: this is not from $(0,1] \rightarrow (0,1)$ and also the brackets are different.
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