Tuesday, August 30, 2016

sequences and series - Evaluating N-th partial sums of polynomials











How can I find Nn=1n2n? Wolfram Alpha will tell you that it is N3(N1)(N+1), and given the famous formulas for Nn=1n2 and Nn=1n, you could piece together the first. But is there some sort of a general method here that might be of use in evaluating these kinds of partial sums?


Answer



I'm not sure what you mean by general but here are two ways to find Nn=1p(n) for p a polynomial.




  • If p has degree d, find the value of the sum for d+2 values of N and use Lagrange interpolation.


  • Write p(n) in the binomial basis (nk) and use sum-of-column identity in the Pascal triangle.




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