(rr)+(r+1r)+(r+2r)+⋯+(nr)=(n+1r+1)
I don't have much experience with combinatorial proofs, so I'm grateful for all the hints.
(Presumptive) Source: Theoretical Exercise 1.11, P18, A First Course in Pr, 8th Ed, by S Ross
I have injection f:A→B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...
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