Find the eigenvalues (with multiplicities) of the matrix $M=M_{a,b}\in Mat_n(\mathbb R)$ that has $a$'s on the main diagonal and $b$'s elsewhere.
I tried to adapt the great method suggested by @Lord Shark the Unknown in this answer.
For simplicity first assume $a < b$. Then $M=B-(b-a)I$, where $B$ is the matrix with $b$'s everywhere. We have $$\det(tI-M)=\det(tI-B+(b-a)I)=\det([t+b-a]I-B).$$ Thus it suffices to find the eigenvalues with multiplicities of $B$. The product of eigenvalues is $0$, the sum is $nb$. But the only thing I can conclude from this is that there is the eigenvalue $0$ of unknown multiplicity. How to find the other eigenvalues and their multiplicities?
Answer
Think about the possible eigenvectors.
You can have an eigenvector with all the entries are $1$, giving an eigenvalue of $a+(n-1)b$. (with multiplicity of $1$)
You can have eigenvectors with one entry $1$ , one entry $-1$ and all other entries are zero, this gives an eigenvalue of $a-b$ and this eigenspace has multiplicity $n-1$.
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