limx→2√x2−4x−2
Am I correct in thinking the limit does not exist? Since as x approaches 2 from the right the function increases to infinity and a limit cannot equal infinity. Thanks!
Answer
limx→2+√x2−4x−2=limx→2+√(x−2)(x+2)x−2=limx→2+√(x−2)√(x+2)x−2=limx→2+√(x+2)√(x−2)
Then as you said the denominator tends to 0+ and hence the whole limit tends to +∞
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