the polynomial 6x3−18x2−6x−6 can be factored as 6(x−r)(x2+ax+b) for some a,b∈R and where r is a real root fo the polynomial. How would you prove that the polynomial x2+ax+b has no real roots. I know that you can do polynomial long division to get concrete values for a and b but r is a decimal so the long division would be messy and inaccurate, but other then that method I have no idea how i would prove that it has no real roots.
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