The solution given was:
$3^9 = (27)^3 = 7^3 = 49(7) = 9(7) = 63 = 3 $
I understand up to $\ 3^9 = (27)^3 $ But after that I am lost. Can someone explain how to solve this and what is going on here?
Answer
The $27$ was replaced with a $7$ because $27\pmod{10}=7$. The same concept arose with the $49$ later, as $49\pmod{10}=9$, and likewise $63\pmod{10}=3$. This is why the values greater than $10$ are switched.
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