Friday, December 13, 2019

Finite field isomorphic to mathbbFpn.

1) Let p prime and n1 an integer. Show that there is a finite field of order pn in an algebraic closure Falgp and that all finite field is isomorphic to exactly one field Fpn



2) Let Fq a finite field and n1 an integer. Let Falgq an algebraic closure. Show that there is a unique extension field of Fq of degree n.



1) By Fermat theorem, for all αFp, αpα(modp). In particular, since Falgp is a closure algebraic, if βFalgp, the minimal polynomial p(X)=a0+a1X+...+anXnFp[X] split over Falgp. In particular, p(X)=a0+...+anXn=ap0+ap1X+...+apnXn, and thus, P(X)=0Fp(X). Therefore fFp[Xp], in particular, P(X)=P(Xp)=P(X)p and thus Frob:FpFpxxp is surjective and thus bijective.


Q1) I'm really not sure about my implication of Frob surjective.


Q2) How can I continue ?


2) By 1) Fq is isomorphic to an Fpn. We have that XqnX split over Fqn.


Q3) It's in written in my course, but I can't prove it. Any idea ?


Q4) I don't know how to continue

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