1) Let p prime and n≥1 an integer. Show that there is a finite field of order pn in an algebraic closure Falgp and that all finite field is isomorphic to exactly one field Fpn
2) Let Fq a finite field and n≥1 an integer. Let Falgq an algebraic closure. Show that there is a unique extension field of Fq of degree n.
1) By Fermat theorem, for all α∈Fp, αp≡α(modp). In particular, since Falgp is a closure algebraic, if β∈Falgp, the minimal polynomial p(X)=a0+a1X+...+anXn∈Fp[X] split over Falgp. In particular, p(X)=a0+...+anXn=ap0+ap1X+...+apnXn, and thus, P′(X)=0∈Fp(X). Therefore f∈Fp[Xp], in particular, P(X)=P(Xp)=P(X)p and thus Frob:Fp⟶Fpx⟼xp is surjective and thus bijective.
Q1) I'm really not sure about my implication of Frob surjective.
Q2) How can I continue ?
2) By 1) Fq is isomorphic to an Fpn. We have that Xqn−X split over Fqn.
Q3) It's in written in my course, but I can't prove it. Any idea ?
Q4) I don't know how to continue
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