Problem :
For the series S=1+1(1+3)(1+2)2+1(1+3+5)(1+2+3)2+1(1+3+5+7)(1+2+3+4)2+⋯
Find the nth term of the series.
We know that nth can term of the series can be find by using Tn=Sn−Sn−1
Sn=1+∑(n(n+1)2)2(2n−1)2
⇒Sn=n4+5n2+2n3−4n+1(2n−1)2
But I think this is wrong, please suggest how to proceed thanks..
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