Why does 1+2+⋯+2003=2004⋅20032?
Sorry if this is missing context; not really much to add...
Answer
S=1+2+3+…+2001+2002+2003S=2003+2002+2001+…+3+2+12S=2004+2004+2004+…+2004+2004+2004
There are 2003 columns, so 2S=2003⋅2004, and therefore S=2003⋅20042.
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