I came across this problem in a Linear Algebra text today:
Let u and v be distinct vectors in a vector space V over a field F. Prove that {u,v} is linearly independent if and only if {u+v,u−v} is linearly independent.
Working on (⇒), I must show that
c1(u+v)+c2(u−v)=0⟹c1=c2=0, where c1,c2∈F.
Using linear independence of {u,v} I arrive at the equation c1+c1=0. However, if F=Z2 then 1+1=0. Also, if c1 and c2 were "integers" then in a field of characteristic 2 I have
c1+c1=(1+⋯+1)⏟c1 times+(1+⋯+1)⏟c1 times=(1+1)+⋯+(1+1)=0+⋯+0=0
However, I'm assuming that they're integers and I'm not sure (as for example R is a field which isn't only integers) that x+x=0 in any field with characteristic 2. Can someone clarify?
Also, I see often the restriction that F be of characteristic not equal to 2. Why is that?
My knowledge of fields is very limited so any references would also be appreciated.
Thank-you.
Answer
The statement you are trying to prove is, indeed, not true if the field has characteristic 2. If u=(1,0) and v=(0,1) then u and v are linearly independent but u+v=u−v=(1,1).
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