Let $ (X, \Sigma, \mu) $ it will be a space with measure.
$\mu$ is $\sigma$-finite measure if it exist sequence of sets $X_{i} \in \Sigma $ and $\cup_{i=1}^{\infty}X_{i}=X$ and $\mu(X_{i})<\infty$ for all i
$\mu$ is semi-finite measure if for all $G \in \Sigma $ and $\mu (G)=\infty$ it exist $H \in \Sigma$ and $H \subset G$ and $0<\mu(H)<\infty$
Show that if $\mu$ is $\sigma$-finite measure then $\mu$ is semi-finite measure
No comments:
Post a Comment