Tuesday, January 22, 2019

calculus - Limit problem ex without L'Hôpital's rule




limx1ex2x1+ex2x


I solved this limit problem by applying L'Hôpital's rule and I got 1.



Question: how to solve this limit without L'Hopital rule and Taylor series?


Answer



hint:



Divide Numerator and Denominator by ex2x



limx1ex2x1+ex2x=limx1ex2x11ex2x+1




Now, limx1ex2x=0, since limxx2x=+ and limxex=+
 Rqrd. limit=1


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