Given 3 arithmetic progressions with same difference d:
(1) a1,a2,a3,... (2) b1,b2,b3,... (3) c1,c2,c3,....
defined: Sn=a1+a2+a3+...+an
Tn=b1+b2+b3+...+bn
Rn=c1+c2+c3+...+cn
Need to prove that if a1,b1,c1 is an arithmetic progression so Sn,Tn,Rn is also an arithmetic progression.
I tried to use the fact that 2b1=a1+c1 and a2−a1=b2−b1=c2−c1=d but i'm stuck
Any idea?
Thanks.
EDIT - an,bn,cn are arithmetic progressions
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