Thursday, November 14, 2019

Proof by induction help. I seem to be stuck and my algebra is a little rusty


Stuck on a homework question with mathematical induction, I just need some help factoring and am getting stuck.


$\displaystyle \sum_{1 \le j \le n} j^3 = \left[\frac{k(k+1)}{2}\right]^2$


The induction part is: $\displaystyle \left[\frac{k(k+1)}{2}\right]^2 +(k+1)^3$ is where I am having a problem.


If you could give me some hints as to where to go since I keep getting stuck or writing the wrong equation.


I'll get to $\displaystyle \left[{k^2+2k\over2}\right]^2 + 2{(k+1)^3\over2}$


Any push in the right direction will be appreciated.


Answer



$(\frac{k(k+1)}{2})^2+(k+1)^3$


$=\frac{k^2(k+1)^2}{4}+(k+1)(k+1)^2$


$=\frac{(k+1)^2}{4}(k^2+4k+4)$



$=\frac{(k+1)^2}{4}(k+2)^2$


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