14+28+316+432+564+⋯∞
This summation was irritating me from the start,I don't know how to attempt this ,tried unsuccessful attempts though.
Answer
S=14+28+316+432+564+⋯2S=12+24+38+416+532⋯(2)−(1):S=12+14+18+116+132⋯=121−12=1
I have injection f:A→B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...
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