Monday, October 7, 2019

sequences and series - limit limlimitsntoinftyleft(sumlimitsni=1frac1sqrti2sqrtnright)



Calculate below limit
limn(ni=11i2n)


Answer



As a consequence of Euler's Summation Formula, for s>0, s1 we have
nj=11js=n1s1s+ζ(s)+O(|ns|),


where ζ is the Riemann zeta function.

In your situation, s=1/2, so
nj=11j=2n+ζ(1/2)+O(n1/2),

and we have the limit
limn(nj=11j2n)=limn(ζ(1/2)+O(n1/2))=ζ(1/2).


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