Can someone suggest how to solve this limit?
$$\lim_{x\to 0}\frac{\sin(\sin x)}{x}$$
If I substitute $y=\sin x$ then $\sin(\sin x)=\sin y$ while $x=\arcsin y$. Then the limit becomes $$\lim_{y\to 0}\frac{\sin y}{\arcsin y}$$
but this form is more complicated than the first one...
Answer
Hint multiply top and bottom by $\sin x$ and break into a product of two limits.
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