Can someone suggest how to solve this limit?
lim
If I substitute y=\sin x then \sin(\sin x)=\sin y while x=\arcsin y. Then the limit becomes \lim_{y\to 0}\frac{\sin y}{\arcsin y}
but this form is more complicated than the first one...
Answer
Hint multiply top and bottom by \sin x and break into a product of two limits.
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