Friday, October 18, 2019

summation - How to evaluate summn=12narctan2ntheta

I need to evaluate mn=12narctan2nθ

as a function of m and θ. All I've done so far is write out the series explicitly:



mn=12narctan2nθ=2arctan2θ+4arctan4θ+8arctan8θ++2marctan2mθ




and I initially considered pairing every two terms up to use the arctanx+arctany trick, but it doesn't work because each arctan term has a different coefficient.

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