I'm having some trouble solving finding the limit of:
$$\lim_{x \to \infty} x \left[ \frac{1}{e} - \left( \frac{x}{x+1} \right)^x \right]$$
I can see that $\left( \frac{x}{x+1} \right)^x = \left( 1 + \frac{-1}{x+1} \right)^x \rightarrow \frac{1}{e}$. That's why I thought the limit is 0. However, according to WolframAlpha it's $-\frac{1}{2e}$.
I tried to write $\frac{1}{e} - \left( \frac{x}{x+1} \right)^x$ as a series but I didn't find a way to...
What's the right approach to find this limit?
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