I'm having some trouble solving finding the limit of:
lim
I can see that \left( \frac{x}{x+1} \right)^x = \left( 1 + \frac{-1}{x+1} \right)^x \rightarrow \frac{1}{e}. That's why I thought the limit is 0. However, according to WolframAlpha it's -\frac{1}{2e}.
I tried to write \frac{1}{e} - \left( \frac{x}{x+1} \right)^x as a series but I didn't find a way to...
What's the right approach to find this limit?
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