trigonometry - Proof of $sin^2 x+cos^2 x=1$ using Euler's Formula

How would you prove $\sin^2x + \cos^2x = 1$ using Euler's formula?

$$e^{ix} = \cos(x) + i\sin(x)$$

This is what I have so far:

$$\sin(x) = \frac{1}{2i}(e^{ix}-e^{-ix})$$

$$\cos(x) = \frac{1}{2} (e^{ix}+e^{-ix})$$

Answer

Multiply $\mathrm e^{\mathrm ix}=\cos(x)+\mathrm i\sin(x)$ by the conjugate identity $\overline{\mathrm e^{\mathrm ix}}=\cos(x)-\mathrm i\sin(x)$ and use that $\overline{\mathrm e^{\mathrm ix}}=\mathrm e^{-\mathrm ix}$ hence $\mathrm e^{\mathrm ix}\cdot\overline{\mathrm e^{\mathrm ix}}=\mathrm e^{\mathrm ix-\mathrm ix}=1$.