So I am asked to find this limit
lim
I know I am supped to use the trig identity \cos(u+v)=\cos(u)\cos(v)-\sin(u)\sin(v) but I am having trouble with the denominator. I am trying to use the common limit \lim_{x \to 0} \frac{sin(x)}{x} but if I expand out every term, I don't have a sin everywhere. How would I deal with that? I tried simplifying the answer but I am honesty getting nowhere.
Could I have some help with how I would simplify? Thanks.
Answer
HINT:
Using Prosthaphaeresis Formula,
\cos(a+2x)+\cos a=2\cos(a+x)\cos x
Now \dfrac{1-\cos x}{x^2}=\left(\dfrac{\sin x}x\right)^2\cdot\dfrac1{1+\cos x}
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