So I am asked to find this limit
limx→02cos(a+x)−cos(a+2x)−cos(a)x2
I know I am supped to use the trig identity cos(u+v)=cos(u)cos(v)−sin(u)sin(v) but I am having trouble with the denominator. I am trying to use the common limit limx→0sin(x)x but if I expand out every term, I don't have a sin everywhere. How would I deal with that? I tried simplifying the answer but I am honesty getting nowhere.
Could I have some help with how I would simplify? Thanks.
Answer
HINT:
Using Prosthaphaeresis Formula,
cos(a+2x)+cosa=2cos(a+x)cosx
Now 1−cosxx2=(sinxx)2⋅11+cosx
No comments:
Post a Comment