Saturday, June 18, 2016

calculus - How to evaluate limlimitsxto0fracsinxx+x3/6x3




I'm unsure as to how to evaluate:



limx0sinxx+x36x3



The limx0 of both the numerator and denominator equal 0. Taking the derivative of both ends of the fraction we get:



limx0x2+2cosx26x2



But I don't know how to evaluate this?




Many thanks for any help.


Answer



You can use l'Hospital as many times as needed as long as the indeterminate forms conditions are fulfilled. In this case, using Taylor series can be helpful, too:



sinx=xx36+x5120=xx36+O(x5)



sinxx+x36x3=O(x5)x3=O(x2)x00


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