Tuesday, June 28, 2016

limit with double summation


Finding value of limnlimmnr=1mrk=1m2n2(m2n2+k2)(n2+r2)



what i try


limmlimnmrk=1m2n2m2n2+k21nnr=1nn2+r2


limnnr=1nn2+r2=1011+x2dx=π4

How do i solve first summation


help me please

No comments:

Post a Comment

analysis - Injection, making bijection

I have injection f:AB and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...