Given a square matrix $A$ that has full row rank we know that the matrix is invertible. So there is a matrix $B$ such that
$$
AB=1
$$
writing this in component notation,
$$
A_{ij}B_{jk}=\delta_{ik}
$$
Now, we tend to write $A^{-1}$ instead of $B$ but let's leave it like that for now.
My question is how can we show that $BA=1$? We mechanically jump to the conclusion that if the inverse exists, $AA^{-1}=A^{-1}A=1$ but how to show that? Equivalently why is the left inverse equal to the right inverse? It seems intuitively obvious!
Thanks a bunch, I appreciate.
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