Say we have f(x+y)=f(x)+f(y)∀x,y∈R and f is continuous at one point at least. I wish to show there must be some c such that f(x)=cx for all x. Think I can do so by first showing f is continuous everywhere I'm not sure how then let f(q)=1 somehow and show that f(q)=cq where q is rational. But then the aim is to show for all real x so I am not sure~
Subscribe to:
Post Comments (Atom)
analysis - Injection, making bijection
I have injection f:A→B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...
-
Recently I took a test where I was given these two limits to evaluate: lim and $\lim_\limi...
-
I need to give an explicit bijection between (0, 1] and [0,1] and I'm wondering if my bijection/proof is correct. Using the hint tha...
-
So if I have a matrix and I put it into RREF and keep track of the row operations, I can then write it as a product of elementary matrices. ...
No comments:
Post a Comment