Find the sum of n terms of the following series:
1+(1+x)+(1+x+x2)+⋯
The nth term (tn) is xn−1x−1, since each term is a Geometric Progression with common ratio x.
Now, I want to find n∑n=1tn. Is it possible to get a telescoping series here?
Answer
HINT:
if x≠1,
∑1≤r≤nxr−1x−1=(∑1≤r≤nxr)−nx−1
Observe the Geometric Progression in the numerator
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