I know that the series converges by d'Alembert ratio test, where lim, but I don't know how to calculate the sum of the serie. Thanks for the help.
Answer
\sum_{k=0}^\infty x^n = \frac{1}{1-x} for |x|<1.
Then
\sum_{k=1}^\infty nx^n = x\times \left(\frac{1}{1-x}\right)' for |x|<1.
No comments:
Post a Comment