Monday, July 15, 2019

divergent series - How is the Riemann zeta function zero at the negative even integers?

I'm not sure if I'm misunderstanding this in any way, but surely evaluating the zeta function at, say, -2, would give




$1 + 2^2 + 3^2 + 4^2 + 5^2 + ...$



which seems to diverge to infinity. What am I missing?

No comments:

Post a Comment

analysis - Injection, making bijection

I have injection $f \colon A \rightarrow B$ and I want to get bijection. Can I just resting codomain to $f(A)$? I know that every function i...