limx→0log(cosx)x2
I've been triyng to:
show $\displaystyle -\frac{\pi}{2}
find a function so that f(x)<log(cosx)x2 and limx→0f(x)=−12
And then apply the squeeze principle, but haven't managed any of these.
Answer
HINT:
log(cosx)x2=log(cos2x)2x2=−12⋅log(1−sin2x)−sin2x⋅(sinxx)2
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