trigonometry - If $0 lt x lt frac{pi}{2}$, is $cos(x) le frac{sin(x)}{x} le frac{1}{cos(x)}$?

How can I find the following product using elementary trigonometry?

Suppose $0 \lt x \lt \frac{\pi}{2}$
is an angle measured in radians. Use the trigonometric circle and
show that $\cos(x) \le \frac{\sin(x)}{x} \le \frac{1}{\cos(x)}$.

I have been trying to solve this question. I can't figure out whether or not the solution requires a trigonometric circle or if it can be done using another method.