Thursday, November 8, 2018

complex analysis - Where does this equation come from?




Since I study 3 years i ask myself very often where does this equation come from?

$$e^{i\theta} = \cos(\theta)+i \sin(\theta)$$
Is it found by series expansion?


Answer



This result is commonly shown via Taylor series, as explained in the comments, and is well-known. I'd like to offer a different sort of proof, for those who are interested, that I believe is easier yet less well-known.



Consider the second order linear differential equation
$$y''=-y$$
We know the most general solution is:
$$y = A\cos{x}+B\sin{x}$$
But $$y = e^{ix}$$ is also a solution, and by existence and uniqueness theorems, that means $$e^{ix} = A\cos{x}+B\sin{x}$$

for some $A,B$. Plugging in $x=0$ for the expression and its first derivative, we see that $A = 1, B = i$.



Thus, $$e^{ix} = \cos{x}+i\sin{x}$$


No comments:

Post a Comment

analysis - Injection, making bijection

I have injection $f \colon A \rightarrow B$ and I want to get bijection. Can I just resting codomain to $f(A)$? I know that every function i...