trigonometry - Limit of trigonometric function: $lim_{xto 0} frac {tan2x}x$

Find $\lim_{x\to 0} \frac {\tan2x}x$

I change tan to sin/cos , we have $\lim_{x\to 0} \frac {\sin2x}{x\cos2x}$

Using l'Hopital's rule,

I get $\lim_{x\to 0} \frac {\cos2x}{(x)(-\sin2x)(\cos2x)}$ = $\lim_{x\to 0} -\frac {1}{(x)(\sin2x)}$

I can't proceed with l'Hopital's rule anymore here as I get 1/0.