For given a∈R there exists unique continuous function f:R→R that satiafy f(x+y)=f(x)f(y) for x,y∈R and f(1)=a.
These theorems were discussed in my mathematical-modeling class and were given to us to prove them.
For given a∈R there exists unique continuous function f:R→R that satiafy f(x+y)=f(x)f(y) for x,y∈R and f(1)=a.
These theorems were discussed in my mathematical-modeling class and were given to us to prove them.
I have injection f:A→B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...
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