Sunday, August 26, 2018

calculus - When a function contains a sequence, and how to find the function's limit?

Suppose limnan=0. Find the limit



limn(1+anxn)n




It's kind intuitive that the answer is 1, but clearly I can't just say that the limits equal limn1n=1.



I feel like I should let y=(1+anxn)n. Then take log so that log(y)=nlog(1+anxn) But L'hopital doesn't apply here either

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