Let a,b,c be integers, prove that if gcd(a,b)=1 then
gcd(ab,c)=gcd(a,c)×gcd(b,c)
I don't know what to do after I got the combinations of ab and c.
I have injection f:A→B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...
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