calculus - Integration of $x^2cdotdfrac{xsec^2x+tan x}{(xtan x+1)^2}$

Integrate

$$\int x^2\cdot\dfrac{x\sec^2x+\tan x}{(x\tan x+1)^2}dx$$

So what is did is integration by parts taking $x^2$ as $u$ and the other part as $v$ . Now I got to use it again which then eventually leads to (integral of $\dfrac1{x\tan x+1}dx $). Can someone help me?