Thursday, August 24, 2017

calculus - Integration of x2cdotdfracxsec2x+tanx(xtanx+1)2

Integrate




x2xsec2x+tanx(xtanx+1)2dx



So what is did is integration by parts taking x2 as u and the other part as v . Now I got to use it again which then eventually leads to (integral of 1xtanx+1dx). Can someone help me?

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