Integrate
∫x2⋅xsec2x+tanx(xtanx+1)2dx
So what is did is integration by parts taking x2 as u and the other part as v . Now I got to use it again which then eventually leads to (integral of 1xtanx+1dx). Can someone help me?
I have injection f:A→B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...
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