Wednesday, November 9, 2016

calculus - How can I find limxto0fractan(3x)sin(8x) without L'Hospital's Rule



Is there a way to solve limx0tan(3x)sin(8x) without using the trig identity tan(3x)=3tan(x)tan3(x)1tan2(x). I want to know because I had to look up this trig identity in order to solve this limit, but if there is a simpler way, then I would like to know it. I don't want to use L'Hospital's Rule because it hasn't been introduced at this point in the book.


Answer



limx0tan(3x)sin(8x)=limx0sin(3x)sin(8x)1cos(3x)=38limx0sin(3x)3x8xsin(8x)1cos(3x)=38




This uses limx0sin(ax)ax=1


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