Is there a way to solve limx→0tan(3x)sin(8x) without using the trig identity tan(3x)=3tan(x)−tan3(x)1−tan2(x). I want to know because I had to look up this trig identity in order to solve this limit, but if there is a simpler way, then I would like to know it. I don't want to use L'Hospital's Rule because it hasn't been introduced at this point in the book.
Answer
limx→0tan(3x)sin(8x)=limx→0sin(3x)sin(8x)⋅1cos(3x)=38limx→0sin(3x)3x⋅8xsin(8x)⋅1cos(3x)=38
This uses limx→0sin(ax)ax=1
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