Evaluate lim
First I tried using L'Hopital's rule..but it's very lengthy
Next I have written the limits as
L=\lim_{x \to 0}\frac{\tan(\tan x)-\sin(\sin x)}{\tan x-\sin x}=\frac{\lim_{x\to 0}\frac{\tan(\tan x)-\sin(\sin x)}{x^3}}{\lim_{x \to 0}\frac{\tan x-\sin x}{x^3}}=\frac{L_1}{L_2}
Now by L'Hopital's Rule we get L_2=0.5
L_1=\lim_{x\to 0}\frac{\tan(\tan x)-\sin(\sin x)}{x^3}
Now L_1 can also be evaluated using three applications of L'Hopital's Rule, but is there any other approach?
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