Monday, November 21, 2016

algebra precalculus - Evaluate limxto0fractan(tanx)sin(sinx)tanxsinx

Evaluate lim




First I tried using L'Hopital's rule..but it's very lengthy



Next I have written the limits as
L=\lim_{x \to 0}\frac{\tan(\tan x)-\sin(\sin x)}{\tan x-\sin x}=\frac{\lim_{x\to 0}\frac{\tan(\tan x)-\sin(\sin x)}{x^3}}{\lim_{x \to 0}\frac{\tan x-\sin x}{x^3}}=\frac{L_1}{L_2}



Now by L'Hopital's Rule we get L_2=0.5



L_1=\lim_{x\to 0}\frac{\tan(\tan x)-\sin(\sin x)}{x^3}



Now L_1 can also be evaluated using three applications of L'Hopital's Rule, but is there any other approach?

No comments:

Post a Comment

analysis - Injection, making bijection

I have injection f \colon A \rightarrow B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...