Saturday, April 30, 2016

algebra precalculus - Simplifying as an exact value (Simplest Radical Form)


Hey, I have a problem: solve for exact value (simplest radical form) $-3\sqrt{27}$ , the result is $-9 \sqrt3$ . I'm in 8th grade studying for a Math placement test to take trigonometry as a freshman next year. This doesn't seem to be covered in my textbook. Can anyone explain to me what's going on here? Thanks!


Answer



Presumably you are familiar with the rule that (for positive $a$ and $b$) $$\sqrt{a\times b}=\sqrt{a}\,\,\times\sqrt{b}$$ Can you see how to break up 27 into $a\times b$ for the right $a$ and $b$?


No comments:

Post a Comment

analysis - Injection, making bijection

I have injection $f \colon A \rightarrow B$ and I want to get bijection. Can I just resting codomain to $f(A)$? I know that every function i...