I really need help with proving this using induction.
n!=[n(n−1)…(n−j+1)](n−j)! for 0≤j≤n
I've tried using brute induction (which is what my prof calls it) and just using n = 1 first, then n = k+1. But I'm not sure what to do with the j? Please help. Anything will be appreciated. Thanks.
Answer
Well...
(n+1)!=(n+1)∗n!=(n+1)[n(n−1).....(n−j+1)](n−j)!;0≤j≤n
=[(n+1)n(n−1)......(n+1−(j+1)+1)](n+1−(j+1))!
=[(n+1)n(n−1).........(n+1−i+1)](n+1−i)!;1≤i≤n+1.
And (n+1)!=[1](n+1−0)!;i=0.
So .... that's it.
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