I need help finding the the following limit:
limx→0sinxx+tanx
I tried to simplify to:
limx→0sinxcosxxcosx+sinx
but I don't know where to go from there. I think, at some point, you have to use the fact that limx→0sinxx=1. Any help would be appreciated.
Thanks!
Answer
sinxx+tanx=1xsinx+tanxsinx→1/2
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