Sunday, June 24, 2018

calculus - Absolute convergence of the series sin(an) implies...?

Can someone please give me a counterexample for the following statement?


If 1sin(an) absolutely converges , then 1an also absolutely converges.


I tried working with an=(1)nn and an=(1)nlnnn , but without any success...


Got any idea?


Thanks a lot !

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