My idea was...
LHS=1sinx−2cosxtan2x=tan2x−sin2xsinxtan2x
from here, I don't know how to continue, please help! thanks
ps, please teach me how to use the "divide" symbol
Answer
Somewhere you'll need a double-angle formula:
tan(2x)=2tanx1−tan2x
or
tan(2x)=sin(2x)cos(2x)=2sinxcosxcos2x−sin2x.
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