Tuesday, September 26, 2017

combinatorics - Hockey-Stick Theorem for Multinomial Coefficients



Pascal's triangle has this famous hockey stick identity.
(n+k+1k)=kj=0(n+jj)
Wonder what would be the form for multinomial coefficients?


Answer



(a1+a2++ata1,a2,,at)=ti=2i1j=1aik=1(a1+a2++ai1+ka1,a2,,aj1,,ai1,k)


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