Let N+ denote the set of natural numbers bigger than 0 and let R+ denote the set of real numbers bigger than 0.
Is there a way to write down an explicit bijection between N+×R+ and R+?
Answer
You can replace N+ by N={0,1,2...}. Also ψ:R+≅[0,1).
Then the required bijection can be
N×R+∋(n,r)⟼n+ψ(r)∈R+ .
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