Check the existence of partial derivatives and continuity of f(x,y) at (1,0) : f(x,y)=3y(x−1)(x−1)2+y2 when (x,y)≠(1,0) and 0 otherwise. I decided to check continuity first - I calculated limit by considering different paths of approach and I got 0 in all cases (confirmed continuity). I checked that in Wolfram and found out that limit shouldn't exist. Where have I done mistake and how to check the existence of partial derivatives?
Answer
Note that if x=y+1, thenf(x,y)=3y22y2=32and that therefore if you approach (1,0) along the line x=y+1, then the limit is 32≠0.
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