One of the basic nonlinear functional equations is the following one:
(f(x))2=xf(2x), x>0.
I found out that functions f(x)=21−xxexp(cx) form the family of solutions of this equation. But do this family cover all possible solutions to this equation? Truly speaking, I have no idea how to answer to this question. Thank you.
Answer
Indeed, this family does not cover all solutions, nor even all continuous ones. The general solution is: take any function defined for x∈[1,2) (which means an awful lot of possibilities, mind you!) and continue it both ways, up and down, using the expressions for f(2x) via f(x) and vice versa.
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